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If sin^(-1)x - cos^(-1) x = (pi)/(6), th...

If `sin^(-1)x - cos^(-1) x = (pi)/(6)`, then what is the value of x ?

A

`(1)/(2)`

B

`(sqrt(3))/(2)`

C

`(-1)/(2)`

D

3

Text Solution

Verified by Experts

The correct Answer is:
B
Given , `sin^(-1)x-cos^(-1)x=(pi)/(6)`
`rArr((pi)/(2)-"cos"^(-1)x)-cos^(-1)x=(pi)/(6)rArr(pi)/(3)=2cos^(-1)x`
`rArrcos^(-1)x=(pi)/(6)rArrx=(sqrt(3))/(2)`
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