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If 0lexle2pi,0le2piandsinx+siny=2, then...

If `0lexle2pi,0le2piandsinx+siny=2`, then the value of x+y is

A

`pi`

B

`(pi)/(2)`

C

`3pi`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
A
Minimum `sintheta=1`, so the equation can have a solution when sin x =1, sin y =1
`rArrx=(pi)/(2),y=(pi)/(2)`
`thereforex+y+pi`
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