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If in a DeltaABC,2cosAsinC=sinB, then t...

If in a `DeltaABC,2cosAsinC=sinB`, then the triangle is

A

equilateral

B

isosceles

C

right angled

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
B
`2cosA.sinC=sin(C+A)`
`=sinC.cosA+cosC.sinA`
`rArrcosAsinC-sinAcosC=0`
`rArrsin(C-A)=0`
`rArrC=A`
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