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The number of solutions of the pair of e...

The number of solutions of the pair of equations `2s in^2theta-cos2theta=0` `2cos^2theta-3sintheta=0` in the interval `[0,2pi]` is

A

zero

B

one

C

two

D

four

Text Solution

Verified by Experts

The correct Answer is:
C

`2sin^(2)theta-cos2theta=0rArr2sin^(2)theta-(1-2sin^(2)theta)=0`
`rArrsin^(2)theta=(1)/(4)`
`rArrsintheta=+-(1)/(2)` …(i)
Also, `2cos^(2)theta=3sinthetarArr2sin^(2)theta+3sintheta-2=0`
`rArr(sintheta+2)(2sintheta+1)=0`
`rArrsintheta=(1)/(2)` ...(ii)
From Eqs . (i0 and (ii), `sintheta=(1)/(2)`
Two solutions exist in `[0,2pi]`.
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