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The equation of pair of straight lines j...

The equation of pair of straight lines joining the point of intersection of the curve `x^2+y^2=4 and y-x=2` to the origin , is

A

`x^2+y^2=(y-x)^2`

B

`x^2+y^2+(y-x)^2=0`

C

`x^2+y^2=4(y-x)^2`

D

`x^2+y^2+4(y-x)^2=0`

Text Solution

Verified by Experts

The correct Answer is:
A
Given , equation of curves are `x^2+y^2=4 and y-x=2`
Now , equation of straight line joining point of intersection of above curve and origin is `x^2+y^2=(y-x)^2`
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Knowledge Check

  • The angle between the pair of straight lines formed by joining the points of intersection of x^2+y^2=4 and y=3x+c to the origin is a right angle. Then c^2 is equal to

    A
    20
    B
    13
    C
    `1//5`
    D
    5

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    A
    `x^2+(3-x)^2 = 9`
    B
    xy=0
    C
    `(3+y)^2+y^2=9`
    D
    `(x-y)^2 = 9`

  • The equation of pair of lines joining origin to the points of intersection of x^2+y^2=9 and x+y=3 is :

    A
    `x^2+(3-x)^2 = 9`
    B
    xy=0
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    `(3+y)^2+y^2=9`
    D
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