Find the distance between the pair of parallel lines `x^2+4x y+4y^2+3x+6y-4=0`

Options

A. `sqrt(5)`
B. `(2)/(sqrt(5))`
C. `(1)/(sqrt(5))`
D. `(sqrt(5))/(2)`

Answer

A

Explanation

Here , `a=1,b=4,g=(3)/(2),f=3,h=2 and c=-4` Then , required parallel distance
`=2sqrt((9)/(4)+4)/(5)=(2sqrt(25))/(2sqrt(5))=(5)/(sqrt(5))xx(sqrt(5))/(sqrt(5))=sqrt(5)`.