The point of intersection of the pair of straight lines given by `6x^(2)+5xy-4y^(2)+7x+13y-2=0`, is

Options

A. `(1,1)`
B. `(1,-1)`
C. `(-1,1)`
D. `(-1,-1)`

Answer

C

Explanation

Let `f(x,y)=6x^2+5xy-4y^2+7x+13y-3`. Then , the point of intersection of the pair of lines given by
`((bg-fh)/(h^2-ab),(af-gh)/(h^2-ab))=[(-4xx(7)/(2)-(13)/(2)xx(5)/(2))/(((5)/(2))^2-6xx-4),(6xx(13)/(2)-(7)/(2)xx(5)/(2))/(((5)/(2))^2-6xx4)]=(((-28)/(2)-(65)/(4))/((121)/(4)),(39-(35)/(4))/((121)/(4)))=(-1,1)` .