If one of the lines of `m y^2+(1-m^2)x y-m x^2=0` is a bisector of the angle between the lines `x y=0` , then `m` is

Options

A. 3
B. 2
C. `-1//2`
D. `-1`

Answer

D

Explanation

Here, `my (y-mx)+x(y-mx)=0`
i.e., `(y-mx)xx(my+x)=0`
So, the lines are `y=mx and y=(-1//m)x` Bisectors between the lines `xy=0` and `y=x and y=-x`.
Therefore , `m= 1 or -1`.