Home
Class 12
MATHS
If one of the lines of m y^2+(1-m^2)x y-...

If one of the lines of `m y^2+(1-m^2)x y-m x^2=0` is a bisector of the angle between the lines `x y=0` , then `m` is

A

`-(1)/(2)`

B

`-2`

C

`+-1`

D

`2`

Text Solution

Verified by Experts

The correct Answer is:
C
Equation of bisectors of lines `xy=0` are `y=+-x`.
Put `y=+-x` in `my^2+(1-m^2)xy-mx^2=0` , we get `mx^2+-(1-m^2)x^2-mx^2=0`
`rArr (1-m^2)=0`
`therefore m= +-1`.
Promotional Banner

Topper's Solved these Questions

  • PAIR OR STRAIGHT LINES

    MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS|Exercise MHT CET Corner|13 Videos

  • PAIR OR STRAIGHT LINES

    MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS|Exercise PRACTICE EXCERCISE (Excercise 1) (Topical Problems) (General Equation of Second Degree)|20 Videos

  • MOCK TEST 5

    MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS|Exercise MCQS|50 Videos

  • PLANE

    MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS|Exercise MHT CET Corner|9 Videos

Similar Questions

Explore conceptually related problems

If one of the lines of my^(2)+(1-m^(2))xy-mx^(2)=0 is a bisector of the angle between the lines xy=0 , then m is

If one of the lines of my^(2)+(1-m^(2))xy-mx^(2)=0 is a bisector of the angle between the lines xy=0, then m is (a) 1 (b) 2(c)-(1)/(2)(d)-1

If one of the lines of my^(2)+(1-m^(2))xy-mx^(2)=0 is a bisector of the angle between the lines xy=0, then m is 3(b)2(c)-(1)/(2)(d)-1

If one of the lines of my^2+(1-m^2)xy-mx^2=0 is a bisector of the angle between lines xy=0 , then cos ^(-1) (m) is

If 2x+y-4=0 is bisector of the angle between the lines a(x-1)+b(y-2)=0,c(x-1)+d(y-2)=0 then other bisector is

The equation of the bisector of the obtuse angle between the lines x-y+2=0 , 7x+y+1=0 is

If tihe lines 2x-y=0 is the bisector of an angle between the two lines x^(2)+2hxy-3y^(2)=0 then h=

The equation of the bisector of the obtuse angle between the lines x-2y+4=0 and 4x-3y+2=0 is

MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS-PAIR OR STRAIGHT LINES -Excercise 2 (MISCELLANEOUS PROBLEMS)
  1. The distance between the two lines represented by the sides of an equi...

    Text Solution

    |

  2. If the pairs of lines x^(2)+2xy+ay^(2)=0andax^(2)+2xy+y^(2)=0 have e...

    Text Solution

    |

  3. If one of the lines of m y^2+(1-m^2)x y-m x^2=0 is a bisector of the a...

    Text Solution

    |

  4. The angle between the pair of straight lines formed by joining the poi...

    Text Solution

    |

  5. The angle between lines joining origin and intersection points of line...

    Text Solution

    |

  6. If the equation lambdax^2+2y^2-5xy+5x-7y+3=0 represents two straight l...

    Text Solution

    |

  7. If the equation of the pair of straight lines passing through the poin...

    Text Solution

    |

  8. The equations a^2x^2+2h(a+b)xy+b^2y^2=0 and ax^2+2hxy+by^2=0 represent...

    Text Solution

    |

  9. The lines a^2x^2+bcy^2=a(b+c)xy will be coincident , if

    Text Solution

    |

  10. If the slope of one of the lines represented by the equation ax^2+2hxy...

    Text Solution

    |

  11. The equation y^(2)-x^(2)+2x-1=0, represents

    Text Solution

    |

  12. The pair of straight lines passing through that point (1,2) and perpen...

    Text Solution

    |

  13. If two sides of a triangle are represented by x^27xy+6y^2=0 and the ce...

    Text Solution

    |

  14. If the angle between the lines represented by the equation y^2+kxy-x^2...

    Text Solution

    |

  15. If the lines represented by the equation 2x^2-3xy+y^2=0 make angles al...

    Text Solution

    |

  16. The line x-2y=0 will be a bisector of the angle between the lines repr...

    Text Solution

    |

  17. If r(1-m^2)+m(p-q)=0, then a bisector of the angle between the lines r...

    Text Solution

    |

  18. The equation of the perpendiculars drawn from the origin to the lines ...

    Text Solution

    |

  19. The equation 2x^2+4xy-py^2+4x+qy+1=0 will represent two mutually perpe...

    Text Solution

    |

  20. The acute angle formed between the lines joining the origin to the poi...

    Text Solution

    |