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The angle between lines joining origin a...

The angle between lines joining origin and intersection points of line `2x+y=1` and curve `3x^2+4yx-4x+1=0`, is

A

`pi//2`

B

`pi//3`

C

`pi//4`

D

`pi//6`

Text Solution

Verified by Experts

The correct Answer is:
A
Now , homogenising the given curve , we get `3x^2+4xy-4x(2x+y)+(2x+y)^2=0`
`rArr 3x^2+4xy-8x^2-4xy+4x^2+y^2+4xy=0`
`rArr -x^2+y^2+4xy=0`
Now , (Coefficient of`x^2`)+(Coefficient `y^2)=-1+1=0`.
`therefore` Lines are mutually perpendicular.
i.e., Angle between lines in `(pi)/(2)`.
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