The point of itnersection of lines represented by ther equation `3x^2+8xy-3y^2+29x-3y+18=0` is

Options

A. `((3)/(2),(5)/(2))`
B. `((-3)/(2),(-5)/(2))`
C. `(-3,-5)`
D. `(3,5)`

Answer

B

Explanation

Here , `a=3,h=4,b=-3,g=(29)/(2), f=-(3)/(2),c=18`
`therefore` Point of intersection is `((bg-fh)/(h^2-ab),(af-gh)/(h^2-ab))`
`=[(-3xx((29)/(2))-(-(3)/(2))4)/(16+9),(3(-(3)/(2)-((29)/(2))(4)))/(16+9)]`
`=(-(75)/(50),(125)/(50))=(-(3)/(2),(5)/(2))`.