If the lines `x^2+2x y-35 y^2-4x+44 y-12=0a n d5x+lambday-8` are concurrent, then the value of `lambda` is

Options

A. 0
B. 1
C. -1
D. 2

Answer

D

Explanation

Given line is `x^2+2xy-35y^2-4x+44y-12=0`
Here , `a=t,b=-35,c=-12,h=1,g=-2,f=22`
`therefore` Point of intersection `((hf-bg)/(ab-h^2),(gh-af)/(ab-h^2))`
`((22-70)/(-35-1),(-2-22)/(-35-1))=((4)/(3),(2)/(3))`
If the lines are concurrent , then point `((4)/(3),(2)/(3))` will lie on the line `5x+lambda y-8=0`
`5((4)/(3))+lambda((2)/(3))-8=0`
`rArr lambda=2`