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The line drawn from point (4,-1,2) to th...

The line drawn from point (4,-1,2) to the point (-3,2,3) meets a plane at right angle at the point (-10,5,4), then the equation of plane is

A

`7x+3y+z+89=0`

B

`7x-3y-z+89=0`

C

`7x-3y+z+89=0`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
B
Since, the line passing through the points (4,-1,2) and (-3,2,3). So, the Dr's of the line is
`(4+3,-1-2,2-3)i.e.(7,-3,-1)`.
Since, the line is perpendicular to the plane therefore DR's of this line is proportional to the normal of the plane.
`:.` Required equation of plane is
`7(x+10)-3(y-5)-1(z-4)=0`
`rArr" "7x-3y-z+89=0`
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