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If theta is the angel between the planes...

If `theta` is the angel between the planes `2x-y+z-1=0 and x-2y+z+2=0` then `costheta=

A

`2//3`

B

`3//4`

C

`4//5`

D

`5//6`

Text Solution

Verified by Experts

The correct Answer is:
D
Here , `a_(1)=2,b_(1)=-1,c_(1)=1`
`and" "a_(2)=1,b_(2)=-2,c_(2)=1`
`:." "costheta=|{:((2xx1)+(-1xx-2)+(1xx1))/(sqrt(4+1+1)sqrt(1+4+1)):}|=(5)/(6)`
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