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The angle between r=(1+2mu)hat(i)+(2+mu)...

The angle between `r=(1+2mu)hat(i)+(2+mu)hat(j)+(2mu-1)hat(k)` and the plane `3x-2y+6x=0` (where, `mu` is a scalar) is

A

`sin^(-1)((15)/(21))`

B

`cos^(-1)((16)/(21))`

C

`sin^(-1)((16)/(21))`

D

`(pi)/(2)`

Text Solution

Verified by Experts

The correct Answer is:
C

The givan line is `r=(1+2mu)hat(i)(2+mu)hat(j)+(2mu-1)hat(k)`
`=(hat(i)+2hat(j)-hat(k))+mu(2hat(i)+hat(j)+2hat(k))`
The cartesian form of a line is `(x-1)/(2)=(y-2)/(1)=(z+1)/(2)`
Also, given `3x-2y+6z=0`
`:.` Angle between the line and the plane is
`sintheta=(2xx3+1xx(-2)+2xx6)/(sqrt(4+1+4)sqrt(9+4+36))=(6-2+12)/(21)=(16)/(21)`
`rArr" "theta=sin^(-1)((16)/(21))`
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Find the angle between the following pairs of lines : (i) vec(r) = 3 hat(i) + 2 hat(j) - 4 hat(k) + lambda (hat(i) + 2 hat(j) + 2 hat(k) ) . vec(r) = 5 hat(j) - 2 hat(k) + mu ( 3 hat(i) + 2 hat(j) + 6 hat(k)) (ii) vec(r) = 3 hat(i) + hat(j) - 2 hat(k) + lambda (hat(i) - hat(j) - 2 hat(k) ) . vec(r) =(2 hat(i) - hat(j) - 56 hat(k)) + mu ( 3 hat(i) - 5 hat(j) - 4 hat(k)) (iii) (x-2)/(2) = (y - 1)/(5) = (z + 3)/(-3) and (x + 2)/(-1) = (y - 4)/(8) = (z - 5)/(4) (iv) (x - 4)/(3) = (y + 1)/(4) = (z - 6)/(5) and (x-5)/(1) = (2y +5)/(-2) = (z - 3)/(1) (v) (5 -x)/(3) = (y + 3)/(-4) , z = 7 and x = (1-y)/(2) = (z - 6)/(2) (vi) (x + 3)/(3) = (y - 1)/(5) = (z + 3)/(4) and (x + 1)/(1) = (y - 4)/(1) = (z-5)/(2) .

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