The equation of the plane through the line of intersection of the planes `ax + by+cz + d= 0` and `a'x + b'y+c'z + d'= 0` parallel to the line `y=0` and `z=0` is

Options

A. `Pa-P'a'=0`
B. `P//a+P'//a'=0`
C. `Pa+P'a'=0`
D. `P//a=P'//a'`

Answer

D

Explanation

The intersection of two planes is `P+lamdaP'=0` . . . (i)
`rArrax+by+cz+d+lamda(a'x+b'y+c'z+d')=0`
For parallel to X-axis, coefficient of x=0
`rArr" "a+lamdaa'=0rArrlamda=-(a)/(a')`
`:.` From Eq. (i), we get
`P-(a)/(a')P'0rArr(P)/(a)=(P')/(a')`