The equation of a plane through the point `(2, 3, 1)` and `(4, -5, 3)` and parallel to x-axis

Options

A. `x-z-1=0`
B. `4x+y-11=0`
C. `y+4z-7=0`
D. None of these

Answer

C

Explanation

Any plane parallel to X-asis is by +cz+d=0. It passes through (2,3,1) and (4,-5,3), then 3b+c+d=0 and `-5b+3c+d=0`
`rArr" "(b)/(1-3)=(c)/(-5-3)=(d)/(9+5)rArr(b)/(1)=(c)/(4)=(d)/(-7)`
Therefore, the plane parallel to X-asis is
`y+4z-7=0`