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If {:A=[(alpha,0),(1,1)]andB=[(1,0),(5,1...

If `{:A=[(alpha,0),(1,1)]andB=[(1,0),(5,1)]:}`, then te value of `alpha` for which `A^2=B`, is

A

1

B

-1

C

4

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
D
`A^(2)=[(alpha, 0),(1,1)][(alpha, 0),(1,1)]=[(alpha^(2),0),(alpha+1,1)] :' A^(2)=B`
`:.[(alpha^(2),0),(alpha+1,1)]=[(1,0),(5,1)]`
`impliesalpha^(2)=1` and `alpha+1=5impliesalpha=4`
Here, no real values of `alpha` exists.
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