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If A is a skew symmetric matrix of order...

If A is a skew symmetric matrix of order `n` and C is a column matrix of order `nxx1`, then `C^(T)AC` is

A

an identity matrix of ordern

B

an identity of order 1

C

a zero matrix of order 1

D

None of the above

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To solve the problem, we need to analyze the expression \( C^T A C \) where \( A \) is a skew-symmetric matrix of order \( n \) and \( C \) is a column matrix of order \( n \times 1 \). ### Step-by-Step Solution: 1. **Understanding Skew-Symmetric Matrix**: A matrix \( A \) is skew-symmetric if \( A^T = -A \). This means that the transpose of the matrix is equal to the negative of the matrix itself. 2. **Transpose of the Expression**: We start with the expression \( C^T A C \). We will take the transpose of this expression: \[ (C^T A C)^T \] Using the property of transposes, we know that \( (XYZ)^T = Z^T Y^T X^T \). Thus, we can write: \[ (C^T A C)^T = C^T A^T (C^T)^T = C^T A^T C \] Since \( (C^T)^T = C \), we can simplify this to: \[ (C^T A C)^T = C^T A^T C \] 3. **Substituting the Skew-Symmetric Property**: Now, substituting \( A^T = -A \) into our expression: \[ (C^T A C)^T = C^T (-A) C = -C^T A C \] 4. **Setting Up the Equation**: Let \( K = C^T A C \). From the previous step, we have: \[ K^T = -K \] This indicates that \( K \) is equal to its own negative. 5. **Conclusion**: The only matrix that is equal to its own negative is the zero matrix. Therefore, we conclude: \[ K = 0 \] Hence, we have: \[ C^T A C = 0 \] ### Final Answer: Thus, \( C^T A C \) is a zero matrix of order \( 1 \).

To solve the problem, we need to analyze the expression \( C^T A C \) where \( A \) is a skew-symmetric matrix of order \( n \) and \( C \) is a column matrix of order \( n \times 1 \). ### Step-by-Step Solution: 1. **Understanding Skew-Symmetric Matrix**: A matrix \( A \) is skew-symmetric if \( A^T = -A \). This means that the transpose of the matrix is equal to the negative of the matrix itself. 2. **Transpose of the Expression**: ...
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