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If A(theta)=[(1, than theta),(-tan, thet...

If `A(theta)=[(1, than theta),(-tan, theta=1)]` and `AB=l`, then `(sec^(2)theta)B` is equal to

A

`A(theta)`

B

`A((theta)/2)`

C

`A(-theta)`

D

`A(-(theta)/2)`

Text Solution

Verified by Experts

The correct Answer is:
C

Given `AB=l`
`impliesB=A^(-1)impliesB=1/(|A|)adj(A)`
`=1/(1+tan^(2)theta)[(1,-tan theta),(tan theta,1)]`
`B=1/(sec^(2)theta)[(1,-tan theta),(tan theta,1)]`
`implies(sec^(2) theta)B=[(1,-tan theta),(tan theta,1)]=A(-theta)`
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