if[{:(2,1),(3,2):}]A[{:(-3,2),(5,-3):}]=...

`if[{:(2,1),(3,2):}]A[{:(-3,2),(5,-3):}]=[{:(1,0),(0,1):}],"then" A=?`

`[(1,1),(1,0)]`

`[(1,1),(0,1)]`

`[(1,0),(1,1)]`

`[(0,1),(1,1)]`

Text Solution

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The correct Answer is:

`[(2,1),(3,2)]A[(-3,2),(5,-3)]=[(1,0),(0,1)]`
`:.A=[(2,1),(3,2)]^(-1)[(1,0),(0,1)][(-3,2),(5,-3)]^(-1)`
`=-[(2,-1),(-3,2)][(1,0),(0,1)][(-3,-2),(-5,-3)]`
`=[(2,-1),(-3,2)][(3,2),(5,3)]=[(1,1),(1,0)]`

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