If matrix A=[(a,b),(c,d)], then |A|^(-1)...

If matrix `A=[(a,b),(c,d)]`, then `|A|^(-1)` is equal to

A

`ad-bc`

B

`1/(ad-bc)`

C

`1/(ad-bc)[(d,-b),(-c,a)]`

D

None of the above

Verified by Experts

The correct Answer is:

B

Given `A=[(a,b),(c,d)]`
`|A|=ad-bc`
`:.|A|^(-1)=1/(ad-bc)`

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