Rolle's theorem is not applicable for the function `f(x)=|x|` in the intervel `[-1,1]` because

Options

A. `f(x)` is not continuous on `[-1,1]`
B. `f` is not differentiable on `[-1,1]`
C. `f(-1)!=f(1)`
D. `f(-1)=f(1)!=0`

Answer

B

Explanation

We know that `|x|` is continuous every where and differentiable every where except at
`x=0 epsilon[-1,1)`