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log(10) (4.04), it being given that log(...

`log_(10) (4.04)`, it being given that `log_(10) 4 = 0.6021 and log_(10) e = 0.4343`

A

`1.3963`

B

`1.2171`

C

`1.6021`

D

`1.3026`

Text Solution

Verified by Experts

The correct Answer is:
A
Let `f(x)=log(x)`
`:.f(4+0.04)~=log4+0.04f'(4)`
`implies f(4.04)~=(log_(10)4)(log310)+0.04(1/4)`
`impliesf(4.04)~=(0.6021)(2.3026)+0.01`
`impliesf(4.04)~=1.3963`
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