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If x=t^(2) and y=2t then equation of the...

If `x=t^(2)` and `y=2t` then equation of the normal at `t=1` is

A

`x+y-3=0`

B

`x+y-1=0`

C

`x+y+1=0`

D

`x+y+3=0`

Text Solution

Verified by Experts

The correct Answer is:
A

Given `x=t^(2)` and `y=2t`
`:.` At `t=1, x=1` and `y=2`
Now `(dy)/(dx)=(dy//dt)/(dx//dt)=2/(2t)=1/t`
At `t=1, ((dy)/(dx))_(t=1)=1`
`:.` Equation of normal is `y-2=-1(x-1)`
`impliesx+y-3=0`
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