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(p ^^ ~q) ^^ (~p vv q) is...

`(p ^^ ~q) ^^ (~p vv q)` is

A

a contradiction

B

a tautology

C

Either (a) or (b)

D

Neigher (a) nor (b)

Text Solution

Verified by Experts

The correct Answer is:
A
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Answer the following questions Without using truth table show that (p vv q) ^^ (~p vv ~q) -= (p vv ~q) ^^ (~p vv q)

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Knowledge Check

  • Negation of (~p ^^~ q) vv (~p vv r) is

    A
    `(p vv q) ^^ (p ^^ ~r)`
    B
    `(p ^^ q) vv (p ^^ ~r)`
    C
    `(p ^^ q) ^^ (p ^^ ~r)`
    D
    `(p vv q) vv (p ^^ ~r)`
  • ~[(p ^^ q)to(~p vv q)] is a

    A
    tautology
    B
    contradiction
    C
    Neither (a) nor (b)
    D
    Either (a) or (b)
  • Quivalent circuit for the logical expression (~p ^^ q) vv (~p ^^ ~q) vv (p ^^ ~q) is

    A
    B
    C
    D
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    The dual of the statement ((p^^ q) ^^ ~q)vv (~q) is

    The proposition S : (p rArr q) iff (~p vv q) is a

    Let p and q be two statements. Then, (~p vv q) ^^ (~p ^^ ~q) is a

    Simplify (p vv q) ^^ (p vv ~q) .

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