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The lines (x-1)/(2)=(y+1)/(2)=(z-1)/(4) ...

The lines `(x-1)/(2)=(y+1)/(2)=(z-1)/(4) and (x-3)/(1)=(y-6)/(2)=(z)/(1)` intersect each other at point

A

(-2,-4,5)

B

(-2,-4,-5)

C

(2,4,-5)

D

(2,-4,-5)

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To find the intersection point of the given lines, we will first express both lines in parametric form and then solve for the parameters to find the intersection point. ### Step 1: Write the equations in parametric form The first line is given by: \[ \frac{x-1}{2} = \frac{y+1}{2} = \frac{z-1}{4} = \lambda \] From this, we can express \(x\), \(y\), and \(z\) in terms of \(\lambda\): - \(x = 2\lambda + 1\) - \(y = 2\lambda - 1\) - \(z = 4\lambda + 1\) The second line is given by: \[ \frac{x-3}{1} = \frac{y-6}{2} = \frac{z}{1} = \mu \] From this, we can express \(x\), \(y\), and \(z\) in terms of \(\mu\): - \(x = \mu + 3\) - \(y = 2\mu + 6\) - \(z = \mu\) ### Step 2: Set the equations equal to find the intersection Now we will set the equations for \(x\), \(y\), and \(z\) from both lines equal to each other: 1. For \(x\): \[ 2\lambda + 1 = \mu + 3 \quad \text{(1)} \] 2. For \(y\): \[ 2\lambda - 1 = 2\mu + 6 \quad \text{(2)} \] 3. For \(z\): \[ 4\lambda + 1 = \mu \quad \text{(3)} \] ### Step 3: Solve the equations From equation (3): \[ \mu = 4\lambda + 1 \] Substituting \(\mu\) into equation (1): \[ 2\lambda + 1 = (4\lambda + 1) + 3 \] \[ 2\lambda + 1 = 4\lambda + 4 \] Rearranging gives: \[ 2\lambda - 4\lambda = 4 - 1 \] \[ -2\lambda = 3 \quad \Rightarrow \quad \lambda = -\frac{3}{2} \] Now substitute \(\lambda = -\frac{3}{2}\) back into equation (3) to find \(\mu\): \[ \mu = 4\left(-\frac{3}{2}\right) + 1 = -6 + 1 = -5 \] ### Step 4: Find the coordinates of the intersection point Now we can find the coordinates of the intersection point using either line. We'll use the first line: - For \(x\): \[ x = 2\left(-\frac{3}{2}\right) + 1 = -3 + 1 = -2 \] - For \(y\): \[ y = 2\left(-\frac{3}{2}\right) - 1 = -3 - 1 = -4 \] - For \(z\): \[ z = 4\left(-\frac{3}{2}\right) + 1 = -6 + 1 = -5 \] Thus, the intersection point is: \[ (-2, -4, -5) \] ### Final Answer: The lines intersect at the point \((-2, -4, -5)\).

To find the intersection point of the given lines, we will first express both lines in parametric form and then solve for the parameters to find the intersection point. ### Step 1: Write the equations in parametric form The first line is given by: \[ \frac{x-1}{2} = \frac{y+1}{2} = \frac{z-1}{4} = \lambda \] ...
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