A dies is thrown four times. The probability of getting perfect square in at least one throw is

Options

A. `(16)/(81)`
B. `(65)/(81)`
C. `(23)/(81)`
D. `(58)/(81)`

Answer

B

Explanation

A die is thrown fourr time
`thereforen=4`
p (probability o gettinng perfect square i.e., 1,4)
here, `p=(2)/(6)=(1)/(3)`
`q=1-p=1-(1)/(3)=(2)/(3)`
`therefore` Required probability
`=P(Xge1)=1-P(X=0)`
`=1-.^(4)C_(0)((1)/(3))^(@)((2)/(3))^(4)=1-(16)/(81)=(65)/(81)`