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In a bionomial distribution, mean is 18 ...

In a bionomial distribution, mean is 18 and variance is 12 then p= . . . .

A

`(2)/(3)`

B

`(1)/(3)`

C

`(3)/(4)`

D

`(1)/(2)`

Text Solution

Verified by Experts

The correct Answer is:
B
We know that, mean=np=18
and variance =n p q=12
Now, `(npq)/(np)=(12)/(18)impliesq=(2)/(3)`
`thereforep=1-q=1-(2)/(3)=(1)/(3)`
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