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If A=[(1+2i,i),(-I,1-2i)], where i=sqrt(...

If `A=[(1+2i,i),(-I,1-2i)]`, where `i=sqrt(-1)`, then `A(adjA)=`. . .

A

`-2l`

B

`2l`

C

`5l`

D

`4l`

Text Solution

Verified by Experts

The correct Answer is:
D
We have, `A=[(1+2i,i),(-I,1-2i)] `
`|A|=|(1+2hati,i),(-I,1-2i)|=(1+2i)(1-2i)+i^(2)`
`=1-(2i)^(2)+(-1)=1+4-1=4`
`thereforeA(adjA)=|A|l=4l`
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