Find the equation of the circle passing ...

Find the equation of the circle passing through `(-2, 14)` and concentric with the circle `x^2+y^2-6x-4y-12=0.`

A

`x^(2)+y^(2)-6x-4y+4=0`

B

`x^(2)+y^(2)-6x-4y+9=0`

C

`x^(2)+y^(2)-6x-4y-4=0`

D

`x^(2)+y^(2)-6x-4y-9=0`

Text Solution

Verified by Experts

The correct Answer is:

A

Given equation of circle
`x^(2)+y^(2)-6x-4y-12=0` . . . (i)
Centre of circle (i) is (3,2)
Equation of circle concentric with circle (i) and touching the Y-axis is
`(x-0)(x-1)+(y-0)(y-1)=0`
`impliesx^(2)-2+y^(2)-y=0`
`impliesx^(2)+y^(2)-x-y=0`

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