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(1-2[cos60^(@)-cos80^(@)])/(2sin10^(@))=...

`(1-2[cos60^(@)-cos80^(@)])/(2sin10^(@))`= . .

A

2

B

1

C

`(1)/(2)`

D

`(3)/(2)`

Text Solution

Verified by Experts

The correct Answer is:
B
We have, `(1-2(cos60^(@)-cos80^(@)))/(2sin10^(@))`
`=(1-2((1)/(2)-cos80^(@)))/(2sin10^(@))=(2cos80^(@))/(2sin10^(@))`
`=(cos(90^(@)-10^(@)))/(sin10^(@))=(sin10^(@))/(sin10^(@))=1`
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MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS-SOLVED PAPER 2019-MCQS
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