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The differential equation of all circles...

The differential equation of all circles in the first quadrant which touch the coordiante axes is of order

A

two

B

three

C

one

D

four

Text Solution

Verified by Experts

The correct Answer is:
C
Equation of the circle touching both axes is
`x^(2)+y^(2)-2ax-2ay+a^(2)=0`
Here, number of arbitrary constant is one which is equal to the order of its differential equation.
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