Let `x = 33^n` . The index n is given a positive integral value at random. The probability that the value of x will have 3 in the units place is

If x = 33^(n) , where n is a positive integral value, then what is the probability that x will have 3 at unit place?

If n is a positive integer then the probability that 3^(n) has 3 at unit place is

If n is a positive integer then the probability that 3^(n) has 3 at unit place is

If x is an even number,then x^(4n), where n is a positive integer,will always have zero in the units place (b) 6 in the units place either 0 or 6 in the units place (d) None of these

For every positive integral value of n, 3 ^(n) gt n^(3) when

if x^n - 1 is divisible by x - k , then the least positive integral value of k is

If x^(n)-1 is divisible by x-k then the least positive integral value of k is

1000 ! Is divisible by 10^n . Find the largest positive integral value of n .