A piece of ice of mass of `100g` and at temperature `0^(@)C` is put in `200g` of water of `25^(@)` How much ice will melt as the temperature of the water reaches `0^(@)C`? The specific heat capacity of water`= 4200 J kg ^(-1)K^(-1)` and the latent heat of ice `= 3.36 xx 10^(5)J kg^(-1)`

Explanation

To solve the problem, we will follow these steps:

### Step 1: Calculate the heat released by the water as it cools down from 25°C to 0°C.

We use the formula for heat transfer:
\[ Q = m \cdot c \cdot \Delta T \]
where:
- \( m \) = mass of the water = 200 g = 0.2 kg
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