A cabe of iron (density`= 8000kg m^(-1)` specific beat capacity `= 470g J kg^(-1)K^(-1))` is heated to a high temperature and is placed on a larger block of ice at `0^(@)C` The cubemelts the ice below it displaces the water and sinks in the final equilibriumposition its upper surface just inside the ice calculate th initial temperature of the cube .Noglect any loss of head outside the ice and the cube .The density of ice `= 900 kg m^(-1)` and the latent head of fasion of ice `= 3.36 xx 10^(5)J kg^(-1)`

Answer

C

Explanation

Let the velume of the cube = V
So volume of ice displace = V
Let the initial the tamp be T K
`Mass of cube = 8000V//kg`
We know, beat gained = beat lost
`rArr 8000v xx 470 xx (T - 273)`
`= 900V xx 3.38 xx 10^(8)`
`rArr 376 T - 376 xx 273 = 30420`
`rArrT= (30420 + 102648)/(376)`
`= (133068)/(376)`
` = 353.9042^(@)K`
` = 80^(@)C`