A block of mass `100g` slides on a rought horizontal surface .If the speed of the block decreases from `10ms^(-1) to 5ms^(-1)`, find the thermal energy developed in the process

Answer

C

Explanation

Thermal energy developed `= change in K.E.
`= (1)/(2) xx (100)/(1000) xx 100- (1)/(2) xx (100)/(1000) xx 25`
= 5 - ((5)/(4)) = (15)/(4) = 3.75J`