the pressure of a gas change linearly with volume from 10kPa, 200 cc to 50 kPa, 50 cc. (a) calculate the work done by the gas, (b) what is the change in the internal energy of the gas ?

Answer

A, B, D

Explanation

`P_10 kP_a`
`=`10xx10^3P-a`
`P_2=50xx10^3P_a`
`V_1=200CC, V_2=50CC`
`(i)work done on the gasltbrge`[((1)/(2))(10+50)xx10^3xx(50-200)xx10^-6]`
`=`-`4*5 J`
`(ii)`DeltaQ=0,`
`So,lt `DeltaU=-DeltaW=4*5J`