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A substance is taken through the process abc as shown in, if the internal energy of the substance increase by 5000 J and a heat of 2625 cal is given to the system, calculate the value of J.

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The correct Answer is:
A, C, D
Now, `DeltaQ = 2625cal .`
` DeltaU = 5000J
Form graph,`
`Delta W = 200xx10^3xx0.03`
` = 6000J`
`Now Delta Q = DeltaW+DeltaU`
`rArr 2625cal = 6000+5000J`
`rArr J = (11000)/(2625) = 4.19J/cal.
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  7. 50 eal of heat should be supplied to take a system from the state A t...

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