A gas is taken along the path AB as shown in , if 70 cal of heat is extracted from the gas in the process, calculate the change in the internal energy of the system.

Answer

A, B, D

Explanation

Delta Q = 70cal = (70xx4.2)J`
`Delta W = (1)/(2)xx(200+500)xx10^3xx150xx10^(-6)`
` = (1)/(2)xx700xx150xx10^(-3)`
` = 525xx10^(-1) = 52.5J`
`Delta U = ?`
`DeltaQ = DeltaU+Delta W`
`rArr -294 = Delta U+52.5`
`rArr Delta U = -294-52.5 = -346.5J