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The internal energy of a gas is given by...

The internal energy of a gas is given by `U=1.5pV`. It expands from `100cm^2` to `200cm^3` against a constant pressure of `1.0xx10^5Pa`. Calculate the heat absorbed by the gas in the process.

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The correct Answer is:
B
Delta U = 1.5pV`
`DeltaV = (20-100)cm^3 = 100cm^3`
` = 10^(-4)m^3`
`P = 1xx10^5pa`
`Delta U = 1.5xx10^5xx10^(-4) = 15J`
`Delta W = 10^5xx10^(-4) = 10J`
`DeltaQ = Delta U+DeltaW = 10+15 = 25J`
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