One face of a copper cube of edge 10 cm is maintained at `100^(@)C` and the opposite face is maintained at `0^(@)C`. All other surfaces are covered with an insulating material. Find the amount of heat flowing per second through the cube. Thermal conductivety of copper is `385Wm^(-1)`^(@)C^(-1)`.

Explanation

The heat flows from the hotter face towards the collder face. The area of cross section perpendicular to the heat flow is `A=(10cm)^(2)`. The amount of heat flowing per second is `(DeltaQ)/(Deltat)=KA(T_(1)-T_(2))/(x)` . `=(385Wm^(-1)`^(@)C^(-1))xx(0.1m)^(2)xx((100^(@)C-0^(@)C))/(0.1m)` . `=3850W` .