A simple pendulum of length `1m` is allowed to oscillate with amplitude `2^(@)`. it colliates at `T` to the verticle its time period will be (use `g = pi^(2)`)

A simple pendulum of length 1m is allowed to oscillate with amplitude 2^(@) . it collides at T to the vertical its time period will be (use g = pi^(2) )

A simple pendulum of length 1m is allowed to oscillate with amplitude 2^(@) . it collides at T to the vertical its time period will be (use g = pi^(2) )

A simple pendulum of length 1 m, and energy 0.2 J, oscillates with an amplitude 4 cm. When its length is doubled then the energy of oscillation will be

A simple pendulum of length l is made to oscillate with an amplitude of 45 degrees. The acceleration due to gravity is g. Let T_(0) = 2pi sqrt(l//g) . The time period of oscillation of this pendulum will be -

A simple pendulum of length 1m is oscillated at a place where g = 9.8 m//s^(2) . Find the maximum velocity of the bob of the simple pendulum if the amplitude of oscillation is 3 cm.

A simple pendulum oscillates in air with time period T and amplitude A . As the time passes