A ring of mass `10kg` and diameter `0.4m` is rotated about an axis passing through its centre. If it makes `1800` revolutions per minute then , the angular momentum of the ring is

A ring of mass 10 kg and diameter 0.4m is rotated about its axis. If it makes 2100 revolutions per minute, then its angular momentum (in kg m^(2)//s ) will be

A ring of mass 10 kg and diameter 0.4m is rotated about an axis passing through its centre and perpendicular to its plane moment of inertia of the ring is

A ring of mass 10 kg and diameter 0.4 m is rotated about an axis passing through its centre and perpendicular to its plane. Moment of inertia of the ring is

A disc of mass 4 kg and radius 0.2 m, makes 20 rev/s, about an axis passing through its centre and perpendicular to the plane of the disc. The angular momentum of the disc is approximately equal to

A ring of mass 10 kg and diameter 0.4 meter is rotating about its geometrical axis at 1200 rotations per minute. Its moment of inertia and angular momentum will be respectively:-

A ring of mass 10 kg and diameter 0.4 meter is rotating about its geometrical axis at 1200 rotations per minute. Its moment of inertia and angular momentum will be respectively:-

A uniform metre scale of mass 0.2 kg is rotated about an axis passing through its one end and perpendicular to its length at the rate of 60 revolutions/minute. What is its angular momentum?

A circular ring of diameter 40 cm and mass 1 kg rotating about an axis normal to its plane and passing through the centre with frequency of 10 rotations per second. Calculate the angular momentum about its axis of rotation.