सिद्ध कीजिए-
`(1 - sin theta ) (1 + sin theta ) (1 + tan^(2) theta) = 1 `

Show that (1 - sin theta)(1 + sin theta) (1 + tan^2 theta) =1

Prove : ( 1+ tan^2 theta )(1 + sin theta )(1 - sin theta) = 1 .

(iii) ( 1 + tan^2 theta ) ( 1 + sin theta ) ( 1 - sin theta ) =1

Prove: (1 + tan^2 theta)(1+sin theta)(1-sin theta) = 1

(tan A) / (1-cot A) + (cot A) / (1-tan A) = 1 + tan A + cot A = 1 + sec A cos ecA (1 + cos theta + sin theta) / (1 + cos theta-sin theta) = (1 + sin theta) / (cos theta)

The number of roots of (1 - tan theta) (1 + sin 2 theta) = 1 + tan theta " for " theta in [0,2 pi] is

(1)/(1-sin theta)-(1)/(1+sin theta)=2sec theta*tan theta

(1)/(1-sin theta)-(1)/(1+sin theta)=(2tan theta)/(cos theta)

(1 + sin theta-cos theta) / (1 + sin theta + cos theta) = (tan theta) / (2)