The voltage for the cell `Fe | Fe^(2+)(0.0010 M)` || Cu^(2+)(0.10 M) | Cu` is 0.807 V at `25^(@)`C. What is the value of E^(@)`?

For the cell Tl|Tl^(+) (0.001M) ||Cu^(2+) (0.1M) |Cu. E_(cell) at 25^@C is 0.83V which can be increased

For the cell Tl|Tl^(+)(0.001M)||Cu^(2+)(0.01M)|Cu.E_("cell") at 25^(@)C is 0.83V, which can be increased:

For the cell, Tl|Tl^+(0.001)||Cu^(2+)(0.1M)|Cu , E_(cell) at 25^@C is 0.826V. The e.m.f can be increased

A voltaic cell is set up at 25^(@)C with the following half cells : Ag^(+) (0.001M) | Ag and Cu^(2+)(0.10 M)|Cu What would be the voltage of this cell ? (E_("cell")^(@) = 0.46 V)

A voltaic cell is set up at 25^(@)C with following half cells : Ag^(+)(0.001 M)|Ag and Cu^(2+)(0.10 M)|Cu What would be the voltage of this cell ? (E_(cell)^(@)=0.45 V)

Calculate the emf of the given cell: Cu/ Cu^(2+)(0.01M) ∣∣ Cu^(2+) (0.001M)∣Cu is ( E^(@)Cu^(2+) /Cu=+0.34V)

Consider the cell at 25^(@)C Tl"|"Tl^(+)(0.001M)"||"Cu^(2+)(0.10)M)"|"Cu for which e.m.f. is 0.84 V. The e.m.f. of this cell could be increased by