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The small orifice between two communicat...

The small orifice between two communicating vessels have area 1 sq. cm. The surface area of horizontal sections of the first and the second vessel are `10m^2` and `5m^2`. Initially the level of liquid in the first and second vessel is 15 m and 5 m from the orifice. Given that velocity of liquid flow is `v= sigma sqrt(2g(h_(1)-h_(2)))` m/s, where `h_1` and `h_2` is the height of liquid in the two vessels, then the time required for the liquid to reach the same level is `10^t/(15 sigma sqrt(20g)`, where t is equal to _?

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