One of the two events must occur. If the chance of one is 2/3 of the other, then odds in favour of the other are

Only one of the two events A and B must occur. If P(A) = (2)/(3)P(B) , the odds in favour of B are

One of the two events A and B must occur. If P(A) = 2/3. P(B), the odds in favour of B are

If the probability of occurrence of an event is (3)/(7) , then the odds in favour of the events are_

Find the odd one from the other options :-

Find the odd one different from the other three.

In a game of chess,the chance of A's win is three times the chance of a draw.The chance B's win is two times the chance of a draw.If they agree to play 3 games, then the odds in favour of they win alternately is [....... (No match is draw)

The chance of an event happening is the square of the chance of a second event but the odds against the first are the cube of the odds against the second. The chances of the events are

The chance of an event happening is the square of the chance of a second event but the odds against the first are the cube of the odds against the second.The chances of the events are

The chance of an event happening is the square of the chance of a second event but the odds against the first are the cube of the odds against the second. The chances of the events are