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[" 2.K,for water is "1.86K" kg moth.If y...

[" 2.K,for water is "1.86K" kg moth.If your automblile radiator holds "1.0kg" of water,how many "],[" of ethyene glycol "(C_(2)H_(6)o_(2))" must you add to get the freesing point of the solution low "],[-2.8^(@)C" ? "],[[" (1) "27g," (2) "72g," (3) "93g," (4) "39g]]

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K_(f) for water is 1.86 K kg mol^(-1) . If your automobile radiator holds 1.0 kg of water, how many grams of ethylene glycol (C_(2)H_(6)O_(2)) must you add to get the freezing point of the solution lowered to -2.8^(@)C ?

K_(f) for water is 1.86 K kg mol^(-1) . IF your automobile radiator holds 1.0 kg of water, how many grams of ethylene glycol (C_(2)H_(6)O_(2)) must you add to get the freezing point of the solution lowered to -2.8^(@)C ?

K_(f) for waer is 1.86 K kg mol^(-1) . If your automobile radiator holds 1.0 kg of water, how many grams of ethylene glycol (C_(2)H_(6)O_(2)) must you add to get the freezing point of the solution lowered to -2.8^(@)C ?

K_(f) for waer is 1.86 K kg mol^(-1) . If your automobile radiator holds 1.0 kg of water, how many grams of ethylene glycol (C_(2)H_(6)O_(2)) must you add to get the freezing point of the solution lowered to -2.8^(@)C ?

K_f for water is 1.86K kg mol^-1 . If your automobile radiator holds 1.0 kg of water, how many grams of ethylene glycol (C_2H_6O_2) must you add to get the freezing point of the solution lowered to 0.8^@C ?

K_(f) for water is 1.86 K kg "mol"^(-1) . If your automobile radiator holds 1.0 kg of water, how many grams of ethylene glycol (C_(2)H_(6)O_(6)) must you add to get the freezing point of the solution lowered to - 2.8^(@)C ?

k_f for water is 1.86 k kg mol^(-1) If your automobile radiator holds 1.0 kg of water, how many grams of ethylene glycol (C_2H_6O_2) must you add to get the freezing point of the solution lowered to - 2. 8^@C ?