[" 5.If "2x=3y=4z" ,then "x:y:z" is "],[[" (a) "6:4:3," (b) "5:4:2],[" (c) "2:3:4," (d) None "]]

2x = 3y = 4z, x: y: z

If 2x = 3y = 4z, find x:y: z.

If x^2 + y^2 + z^2 =2 (x-y-z) - 3, then the value of 2x - 3y + 4z is [Assume that x, y, z are all real numbers] :

Let 2x+3y+4z=9,x,y,z>0 then the maximum value of (1+x)^(2)(2+y)^(3)(4+z)^(4) is

The system of equations x+2y+3z=4 , 2x+3y+4z=5 , 3x+4y+5z=6 has a. infinite many solution b.no solution c. unique solution d. none of these.

Solve by matrix method (2/x) + (3/y) + (10/z) =4, (4/x) - (6/y) + (5/z) =1 , (6/x) + (9/y) - (20/z) =2 and x,y, z != 0

2x+3y+4z=9,4x+9y+3z=10,5x+10y+5z=1 then the value of x is